document.write( "Question 1149050: Belmont Records sends a disk jockey 10 new CD releases for possible use. In how many ways can the disk jockey select no more than 8 CDs? \r
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Algebra.Com's Answer #770388 by VFBundy(438)\"\" \"About 
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Selecting \"no more than 8 CDs\" is not only the number of ways he can choose 8 CDs, but also the number of ways he can choose 7,6,5,4,3,2, and 1 CD.
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\n" ); document.write( "Ways to choose 8 CDs: 10C8 = \"10%21%2F%288%21%2A2%21%29\" = 45
\n" ); document.write( "Ways to choose 7 CDs: 10C7 = \"10%21%2F%287%21%2A3%21%29\" = 120
\n" ); document.write( "Ways to choose 6 CDs: 10C6 = \"10%21%2F%286%21%2A4%21%29\" = 210
\n" ); document.write( "Ways to choose 5 CDs: 10C5 = \"10%21%2F%285%21%2A5%21%29\" = 252
\n" ); document.write( "Ways to choose 4 CDs: 10C4 = \"10%21%2F%284%21%2A6%21%29\" = 210
\n" ); document.write( "Ways to choose 3 CDs: 10C3 = \"10%21%2F%283%21%2A7%21%29\" = 120
\n" ); document.write( "Ways to choose 2 CDs: 10C2 = \"10%21%2F%282%21%2A8%21%29\" = 45
\n" ); document.write( "Ways to choose 1 CD: 10C1 = \"10%21%2F%281%21%2A9%21%29\" = 10
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\n" ); document.write( "45 + 120 + 210 + 252 + 210 + 120 + 45 + 10 = 1012
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