document.write( "Question 105421: Hello everyone,\r
\n" ); document.write( "\n" ); document.write( "The question: Find the inverse of the function f(x) = \"+sqrt+%28x%5E2+%2B+%281%2Fx%5E2%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "I am having trouble isolating the y for the inverse function. I would greatly appreciate any help. My work is shown below.\r
\n" ); document.write( "\n" ); document.write( "Thank you very much!\r
\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "My work :\r
\n" ); document.write( "\n" ); document.write( "f(x) = \"+sqrt+%28x%5E2+%2B+%281%2Fx%5E2%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "y = \"+sqrt+%28x%5E2+%2B+%281%2Fx%5E2%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "x = \"+sqrt+%28y%5E2+%2B+%281%2Fy%5E2%29%29+\"\r
\n" ); document.write( "\n" ); document.write( " = \"+sqrt+%28%28y%5E4+%2B+1%29%2Fy%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2+=+%28y%5E4+%2B+1%29%2Fy%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2y%5E2+=+y%5E4+%2B+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2y%5E2+-+y%5E4+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"+y%5E2%28x%5E2+-+y%5E2%29+=+1+\"
\n" ); document.write( "

Algebra.Com's Answer #77038 by TP(29)\"\" \"About 
You can put this solution on YOUR website!
Fine up to \"sqrt+%28y%5E2+%2B+1%2Fy%5E2%29\".
\n" ); document.write( "So we'll go from there.
\n" ); document.write( "x=\"sqrt+%28y%5E2+%2B+1%2Fy%5E2%29\"
\n" ); document.write( "Square both sides:
\n" ); document.write( "\"x%5E2=+y%5E2+%2B+1%2Fy%5E2+=+y%5E4%2Fy%5E2+%2B+1%2Fy%5E2+=+%28y%5E4+%2B+1%29%2Fy%5E2\".
\n" ); document.write( "Now multiply both sides by \"y%5E2\"
\n" ); document.write( "We get:
\n" ); document.write( "\"y%5E2x%5E2+=+y%5E4+%2B+1\"
\n" ); document.write( "Now subtract \"y%5E2x%5E2\" from both sides:
\n" ); document.write( "We get \"y%5E4-x%5E2y%5E2+%2B+1+=+0\" (i)
\n" ); document.write( "Let \"z+=+y%5E2\" and (i) becomes:
\n" ); document.write( "\"z%5E2+-+x%5E2z+%2B+1+=+0\"
\n" ); document.write( "Now using the formula for the solution of \"az%5E2+%2B+bz+%2B+c+%2B+0\" i.e.
\n" ); document.write( "\"z+=+%28-b%2B-sqrt%28b%5E2+-+4ac%29%29%2F2a\"where \"a=1\",\"+b=-x%5E2\" and \"+c=1\"
\n" ); document.write( "we get:
\n" ); document.write( "\"z+=+%28x%5E2%2B-sqrt%28x%5E4+-+4%29%29%2F2\"
\n" ); document.write( "But \"z+=+y%5E2\" and so:
\n" ); document.write( "\"y%5E2+=+%28x%5E2%2B-sqrt%28x%5E4+-+4%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Hence \"y=+sqrt%28%28x%5E2%2B-sqrt%28x%5E4+-+4%29%29%2F2%29\".
\n" ); document.write( "Now there are TWO possible answers for the solution to the equation but only ONE is correct for the inverse function and it is:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+sqrt%28%28x%5E2+%2B+sqrt%28x%5E4+-+4%29%29%2F2%29\"ANS.
\n" ); document.write( "(NB. I'll leave it up to you to work out what \"y+=+sqrt%28%28x%5E2+-+sqrt%28x%5E4+-+4%29%29%2F2%29\" represents.
\n" ); document.write( "You should also use your calculator to check the inverse function answer - I suggest, for example, that you replace x by 4 or a similar small value).
\n" ); document.write( "
\n" ); document.write( "
\n" );