document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1149003>Question 1149003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The surface area of a sphere is directly proportional to the square of its radius.A sphere of radius 10cm must be increased to a radius of xcm if its surface area is to be doubled.find x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770338 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The surface area of a sphere is directly proportional to the square of its radius.A sphere of radius 10cm must be increased to a radius of xcm if its surface area is to be doubled.find x.<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+10sqrt%282%29 ALIGN=MIDDLE  ALT=\"x+=+10sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );