document.write( "Question 1148996: Suppose the average of 999 numbers is also 999. Suppose further that from these numbers you chose 729 of them and their computed average is coincidentally also 729. What would be the average of the remaining numbers? \n" ); document.write( "
Algebra.Com's Answer #770334 by josmiceli(19441)\"\" \"About 
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Let \"+T+\" = the total value of the 999 numbers
\n" ); document.write( "\"+999+=+T%2F999+\"
\n" ); document.write( "\"+T+=+999%5E2+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "Let \"+A+\" = the average of remaining \"+270+\" numbers
\n" ); document.write( "Tje total value of the \"+729+\" number is \"+729%2A729+\"
\n" ); document.write( "\"+999+=+%28+729%5E2+%2B+A%2A270+%29+%2F+999+\"
\n" ); document.write( "\"+999%5E2+=+729%5E2+%2B+270A+\"
\n" ); document.write( "\"+998001+=+531441+%2B+270A+\"
\n" ); document.write( "\"+466560+=+270A+\"
\n" ); document.write( "\"+A+=+1728+\" answer
\n" ); document.write( "Get a 2nd opinion if needed\r
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