document.write( "Question 1148981: For indirect proofs, how can I prove that point O lies on line AD with the givens: Circle O with AB congruent to AC, and line AD is the median to BC with the usage of equidistance theorems? I realized that triangle ADB and ABC are congruent by the SSS postulate, that I may need to draw lines OB and OC, and AD would be a perpendicular bisector of BC. However, I am not certain on how I can use this or if my assumptions are even accurate. \n" ); document.write( "
Algebra.Com's Answer #770329 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Your description of the given information is not sufficient for us to know exactly what the picture is; so there is no point in our trying to help you with your question. \n" ); document.write( "Re-post with a complete description; or post a diagram to any of a number of free hosting sites and include the URL for the diagram in your post. \n" ); document.write( " \n" ); document.write( " |