document.write( "Question 105831: Can you help with this please.\r
\n" ); document.write( "\n" ); document.write( "Show the steps that you would use to solve the following\r
\n" ); document.write( "\n" ); document.write( "5-2/x-6=10-2x/x-6\r
\n" ); document.write( "\n" ); document.write( "Second part to this why isthis not a solution. \r
\n" ); document.write( "\n" ); document.write( "My solution
\n" ); document.write( "5=10-2x/x-6+2/x-6 \r
\n" ); document.write( "\n" ); document.write( "5=12-2x/2x-12\r
\n" ); document.write( "\n" ); document.write( "5=0\r
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\n" ); document.write( "\n" ); document.write( "Thank You
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Algebra.Com's Answer #77032 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"5-2%2F%28x-6%29=10-2x%2F%28x-6%29\"
\n" ); document.write( "\"5=10-2x%2F%28x-6%29%2B2%2F%28x-6%29\"
\n" ); document.write( "\"5=highlight%2812%29-highlight%282x%2F%282x-12%29%29\" \r
\n" ); document.write( "\n" ); document.write( "The highlighted boxes show where you made your mistakes.
\n" ); document.write( "First off, in the second line, you have 10, where did the 12 come from in line 3.
\n" ); document.write( "Second, when you add fractions, you need to have the same denominator. Then you can add or subtract the numerators keeping the same denominator.
\n" ); document.write( "\"A%2FC%2BB%2FC=%28A%2BB%29%2FC\"
\n" ); document.write( "You added denominators.
\n" ); document.write( "Let's go back to your second line.
\n" ); document.write( "\"5=10-2x%2F%28x-6%29%2B2%2F%28x-6%29\"
\n" ); document.write( "\"5=10%2B%282-2x%29%2F%28x-6%29\"
\n" ); document.write( "I'll leave you there. I think you can proceed from here.
\n" ); document.write( "Move that 10 from the right hand side (additive inverse).
\n" ); document.write( "Multiply both sides by the denominator (x-6) and then solve for x.
\n" ); document.write( "Good luck. If you get stuck post another question.
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