document.write( "Question 105831: Can you help with this please.\r
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document.write( "Show the steps that you would use to solve the following\r
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document.write( "5-2/x-6=10-2x/x-6\r
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document.write( "Second part to this why isthis not a solution. \r
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document.write( "My solution
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document.write( "5=10-2x/x-6+2/x-6 \r
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document.write( "5=12-2x/2x-12\r
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document.write( "5=0\r
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document.write( "Thank You
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document.write( "
Algebra.Com's Answer #77032 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The highlighted boxes show where you made your mistakes. \n" ); document.write( "First off, in the second line, you have 10, where did the 12 come from in line 3. \n" ); document.write( "Second, when you add fractions, you need to have the same denominator. Then you can add or subtract the numerators keeping the same denominator. \n" ); document.write( " \n" ); document.write( "You added denominators. \n" ); document.write( "Let's go back to your second line. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I'll leave you there. I think you can proceed from here. \n" ); document.write( "Move that 10 from the right hand side (additive inverse). \n" ); document.write( "Multiply both sides by the denominator (x-6) and then solve for x. \n" ); document.write( "Good luck. If you get stuck post another question. \n" ); document.write( " |