document.write( "Question 1148964: ABCD is a trapezoid in which AD:BC = 2:5. If the area of triangle AMD is 624cm2, find the area of the trapezoid in cm2.
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Algebra.Com's Answer #770305 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Triangles AMD and CMB are similar. Since the bases are in the ratio 2:5, their heights are in the ratio 2:5, and their areas are in the ratio 2^2:5^2 = 4:25.

\n" ); document.write( "So, given that the area of AMD is 624, we know the area of CMB is 624*(25/4) = 3900.

\n" ); document.write( "Triangles AMD and ABD share base AD; and the ratio of their altitudes is 2:(2+5) = 2:7. So the area of triangle ABD is 624*(7/2) = 2184; and then the area of triangle ABM is 2184-624 = 1560.

\n" ); document.write( "By a similar argument, the area of triangle DMC is also 1560.

\n" ); document.write( "So the area of the trapezoid is

\n" ); document.write( "624+3900+2(1560) = 7644 cm^2.

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\n" ); document.write( "Added in response to the reader's question....

\n" ); document.write( "The ratio of similarity between triangles AMD and CMB is 2:5, not 2:7.

\n" ); document.write( "2:7 is the ratio of the height of triangle AMD to the height of the trapezoid.

\n" ); document.write( "2:7 is also the ratio between the heights of triangles AMD and ABD; and between the heights of triangles AMD and DMC.
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