document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148904>Question 1148904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular rock garden with a diameter of 60 feet is placed in the middle of a square grass yard. If the perimeter of the yard is 92 yards, then how much area is covered by grass?\r<BR>\n" );
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document.write( "For all calculations involving π, use π≈3.14.<BR>\n" );
document.write( "Hint: Be careful that you do not do any rounding on answers until the very end of a problem part, or you could create rounding error.\r<BR>\n" );
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document.write( "a) Amount of area covered by grass, measured in square feet = Blank square feet.<BR>\n" );
document.write( "DO NOT TYPE COMMAS. Round your answer to 2 decimal places as needed.\r<BR>\n" );
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document.write( "b) Amount of area covered by grass, measured in square yards = Blank square yards.<BR>\n" );
document.write( "Round your answer to 2 decimal places as needed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770254 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of whole yard is 23^2 yds^2=529 yds^2<BR>\n" );
document.write( "area of circle is pi*r^2, and r=10 yards (30 feet), so 100 pi yds^2=314 yds^2<BR>\n" );
document.write( "the difference between the two is 215 yds^2, which is amount covered by grass. </SPAN>\n" );
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