document.write( "Question 105785: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #77023 by checkley75(3666)\"\" \"About 
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2L+2W=PERIMETER.
\n" ); document.write( "L=3W+8
\n" ); document.write( "2(3W+8)+2W=64
\n" ); document.write( "6W+16+2W=64
\n" ); document.write( "8W=64-16
\n" ); document.write( "8W=48
\n" ); document.write( "W=48/8
\n" ); document.write( "W=6CM FOR THE WIDTH.
\n" ); document.write( "L=3*6+8
\n" ); document.write( "L=18+8
\n" ); document.write( "L=26 CM FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*26+2*6=64
\n" ); document.write( "52+12=64
\n" ); document.write( "64=64\r
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