document.write( "Question 105785: The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #77023 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 2L+2W=PERIMETER. \n" ); document.write( "L=3W+8 \n" ); document.write( "2(3W+8)+2W=64 \n" ); document.write( "6W+16+2W=64 \n" ); document.write( "8W=64-16 \n" ); document.write( "8W=48 \n" ); document.write( "W=48/8 \n" ); document.write( "W=6CM FOR THE WIDTH. \n" ); document.write( "L=3*6+8 \n" ); document.write( "L=18+8 \n" ); document.write( "L=26 CM FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "2*26+2*6=64 \n" ); document.write( "52+12=64 \n" ); document.write( "64=64\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |