document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148852>Question 1148852</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 yd longer than its width.<BR>\n" );
document.write( "If the perimeter of the rectangle is 50 yd, find its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770178 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 yd longer than its width.<BR>\n" );
document.write( "L = w + 5<BR>\n" );
document.write( "or<BR>\n" );
document.write( "L - w = 5<BR>\n" );
document.write( "If the perimeter of the rectangle is 50 yd, <BR>\n" );
document.write( "2L + 2w = 50<BR>\n" );
document.write( "simplify, divide by 2, use elimination with the 1st equation<BR>\n" );
document.write( "L + w = 25<BR>\n" );
document.write( "L - w = 5<BR>\n" );
document.write( "-------------addition eliminates w, find L<BR>\n" );
document.write( "2L + 0 = 30<BR>\n" );
document.write( "L = 30/2<BR>\n" );
document.write( "L = 15 is the length<BR>\n" );
document.write( "then<BR>\n" );
document.write( "15 - 5 = 10 is the width<BR>\n" );
document.write( "\"find its area.\"<BR>\n" );
document.write( "15 * 10 = 150 sq/yds is the area </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );