document.write( "Question 105664: The sum of three consecutive integers is 33 more than the least of the integers. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #77015 by bucky(2189)\"\" \"About 
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The three consecutive integers can be represented as:
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\n" ); document.write( "x
\n" ); document.write( "x+1 and
\n" ); document.write( "x+2
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\n" ); document.write( "The sum of these three is 3x + 3
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\n" ); document.write( "If you take 33 away from this sum, it is to equal the least of the integers which is x.
\n" ); document.write( "So
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\n" ); document.write( "3x + 3 - 33 = x
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\n" ); document.write( "Subtract x from both sides and you get:
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\n" ); document.write( "2x + 3 - 33 = 0
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\n" ); document.write( "Now combine the +3 and -33 and you have:
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\n" ); document.write( "2x - 30 = 0
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\n" ); document.write( "Add 30 to both sides:
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\n" ); document.write( "2x = 30
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\n" ); document.write( "Solve for x by dividing both sides by 2 to get:
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\n" ); document.write( "x = 15
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\n" ); document.write( "So the answer is that the three integers are 15, 16, and 17.
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