document.write( "Question 1148798: The position of a body at time 𝑡 seconds is 𝑠(𝑡) = 𝑡^3 − 9𝑡^2 + 14𝑡 meters. Find the body’s velocity each time the acceleration is zero. \n" ); document.write( "
Algebra.Com's Answer #770142 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The position of a body at time 𝑡 seconds is 𝑠(𝑡) = 𝑡^3 − 9𝑡^2 + 14𝑡 meters. Find the body’s velocity each time the acceleration is zero. \n" ); document.write( "---------- \n" ); document.write( "V is the 1st derivative of position. \n" ); document.write( "s'(t) = 3t^2 - 18t + 14 \n" ); document.write( "============================= \n" ); document.write( "Acceleration is the 2nd derivative of position. \n" ); document.write( "s\"(t) = 6t - 18 \n" ); document.write( "6t - 18 = 0 \n" ); document.write( "t = 3 \n" ); document.write( "------------- \n" ); document.write( "Sub 3 for t in the 1st derivative.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |