document.write( "Question 1148799: The sum of the perimeters of two squares is 80 in., and the area of one is 3 times the area of the other. Find the side length of each square. \n" ); document.write( "
Algebra.Com's Answer #770135 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Let x be side length small square
\n" ); document.write( "and let y be side length of big square.\r
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\n" ); document.write( "\n" ); document.write( "This means \"system%284x%2B4y=80%2Cand%2Cy%5E2=3x%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Simpler system \"x%2By=20%2Cy%5E2%2B3x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=20-x\"
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\n" ); document.write( "\"y%5E2=%2820-x%29%5E2=400-40x%2Bx%5E2\"
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\n" ); document.write( "\"400-40x%2Bx%5E2=3x%5E2\"
\n" ); document.write( "\"200-20x=x%5E2\"
\n" ); document.write( "\"x%5E2%2B20x-200=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-20%2Bsqrt%28400%2B4%2A200%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28x=-10%2B10sqrt%283%29%29\", edge length of smaller square; use it to find y.\r
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\n" ); document.write( "\n" ); document.write( "-----------------------------------------------------mistake-------------------
\n" ); document.write( "Simplified, system is \"system%28x%2By=20%2Cand%2Cy%5E2=3x%5E2%29\".\r
\n" ); document.write( "\n" ); document.write( "Subst for x and simplify,
\n" ); document.write( "\"y%5E2-60y%2B600=0\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28y=60-10sqrt%283%29%29\" or \"cross%28y=60%2B10sqrt%283%29%29\"
\n" ); document.write( "and you can find any corresponding x values.
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