document.write( "Question 105816: How much pure acid should be mixed with 2 gallons of a 50% acid solution in order to get an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #77012 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! sorry for the mistake. I used 5% instead of 50%. \n" ); document.write( "below is the corrected solution & 3 is the answer. \n" ); document.write( "--------------------------------------------------------------------- \n" ); document.write( ".5*2+X=.8(X+2) \n" ); document.write( "1+X=.8X+1.6 \n" ); document.write( "X-.8X=1.6-1 \n" ); document.write( ".2X=.6 \n" ); document.write( "X=.6/.2 \n" ); document.write( "X=3 GALLONS NEEDED OF THE PURE ACID. \n" ); document.write( "PROOF \n" ); document.write( ".5*3+3=.8(3+2) \n" ); document.write( "1.5+3=.8*5 \n" ); document.write( "4=4 \n" ); document.write( " \n" ); document.write( " |