document.write( "Question 105816: How much pure acid should be mixed with 2 gallons of a 50% acid solution in order to get an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #77012 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
sorry for the mistake. I used 5% instead of 50%.
\n" ); document.write( "below is the corrected solution & 3 is the answer.
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\n" ); document.write( ".5*2+X=.8(X+2)
\n" ); document.write( "1+X=.8X+1.6
\n" ); document.write( "X-.8X=1.6-1
\n" ); document.write( ".2X=.6
\n" ); document.write( "X=.6/.2
\n" ); document.write( "X=3 GALLONS NEEDED OF THE PURE ACID.
\n" ); document.write( "PROOF
\n" ); document.write( ".5*3+3=.8(3+2)
\n" ); document.write( "1.5+3=.8*5
\n" ); document.write( "4=4
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