document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148773>Question 1148773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sophie was 28 years old when her daughter Nichole was born. In how many years will Sophie be two years less than six times Nicholes age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770110 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Let x be Nichole's age when Sophie is 2 less than 6 times Nichole's age.<br><BR>\n" );
document.write( "Then of course Sophie's age then will be 6x-2; the DIFFERENCE in their ages will be (6x-2)-x = 5x-2.<br><BR>\n" );
document.write( "The difference in their ages will always be 28 years.  So<br><BR>\n" );
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document.write( "Finish the problem using basic algebra.<br> </SPAN>\n" );
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