document.write( "Question 105817: Melissa invested a sum of money at 3% annual simple interest. She invested three times that sum at 5% annual simple interest. If her total yearly interest from both investments was $7200, how much was invested at 3%? \n" ); document.write( "
Algebra.Com's Answer #77011 by checkley75(3666)\"\" \"About 
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.03X+.05(3X)=7200
\n" ); document.write( ".03X+.15X=7,200
\n" ); document.write( ".18X=7,200
\n" ); document.write( "X=7,200/.18
\n" ); document.write( "X=40,000 IS THE AMOUNT INVESTED @ 3%
\n" ); document.write( "3*40,000=120,000 INVESTED @ 5%
\n" ); document.write( "PROOF
\n" ); document.write( ".03*40,000+.05*120,000=7200
\n" ); document.write( "1,200+6,000=7,200
\n" ); document.write( "7,200=7,200
\n" ); document.write( "
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