document.write( "Question 1148759: A boat travelling at full speed against a current goes 14 kph. Travelling at half speed with current goes 10 kph. Find the rate of the current and the maximum speed of the boat. (use x and y variables and show a full solution please? thanksss!) \n" ); document.write( "
Algebra.Com's Answer #770096 by ikleyn(53763)\"\" \"About 
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\n" ); document.write( "A boat travelling at full speed against a current goes 14 kph. Travelling at half speed with current goes 10 kph.
\n" ); document.write( "Find the rate of the current and the \"highlight%28cross%28maximum%29%29\"  full  speed of the boat in  still water.
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document.write( "Let  \"x\"  be the \"full\" speed of the boat in still water,\r\n" );
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document.write( "and let  \"y\"  be the rate of the current.\r\n" );
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document.write( "Then the effective rate moving upstream is  (x-y) kph.\r\n" );
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document.write( "     the effective speed moving downstream is   \"x%2F2+%2B+y\" kph.\r\n" );
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document.write( "From the condition,\r\n" );
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document.write( "    x - y = 14  kph   (1)\r\n" );
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document.write( "    \"x%2F2\" + y = 10  kph   (2)\r\n" );
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document.write( "Add the equations (1) and (2).  You will get\r\n" );
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document.write( "    \"%283%2F2%29x\" = 14 + 10 = 24,\r\n" );
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document.write( "which implies  x = \"%282%2F3%29%2A24\" = 16 kph.\r\n" );
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document.write( "Then from equation (1),  y = x - 14 = 16 - 14 = 2 kph.\r\n" );
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document.write( "ANSWER.  The \"full\" speed of the boat in still water  is 16 kph;\r\n" );
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document.write( "         the rate of the current is  2 kph.\r\n" );
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\n" ); document.write( "\n" ); document.write( "What you will do with my full solution / solutions ?\r
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\n" ); document.write( "\n" ); document.write( "Will sell to other web-sites ?\r
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