document.write( "Question 105662: If the measure of one angle of a triangle is equal to the sum of the measures of the other two angles, then the triangle is always:
\n" ); document.write( "(1)acute
\n" ); document.write( "(2)obtuse
\n" ); document.write( "(3)isoceles
\n" ); document.write( "(4)right
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Algebra.Com's Answer #77008 by bucky(2189)\"\" \"About 
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In a triangle the measures of the three angles totals to 180 degrees. Suppose we have
\n" ); document.write( "the measures of angles A, B, and C in a triangle and identify these measures as mA, mB, and mC.
\n" ); document.write( "Since the total of these three measures is 180 degrees for this triangle, we can write the equation:
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\n" ); document.write( "mA + mB + mC = 180
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\n" ); document.write( "Now in accordance with the problem we are told that the measure of one of the angles,
\n" ); document.write( "say mA, is equal to the sum of the measures of the other two angles ... mB + mC. In equation
\n" ); document.write( "form this is:
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\n" ); document.write( "mA = mB + mC
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\n" ); document.write( "So for mB + mC in the equation for all three angles totaling 180 we can substitute
\n" ); document.write( "mA because mA is equal to mB + mC.
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\n" ); document.write( "Start with:
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\n" ); document.write( "mA + mB + mC = 180
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\n" ); document.write( "In place of mB + mC substitute mA to get:
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\n" ); document.write( "mA + mA = 180
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\n" ); document.write( "Add the terms on the left side to get 2mA and the equation becomes:
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\n" ); document.write( "2mA = 180
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\n" ); document.write( "Solve for mA by dividing both sides by 2 to reduce the equation to:
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\n" ); document.write( "mA = 180/2 = 90 degrees
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\n" ); document.write( "Since mA = 90 degrees, the triangle has a right angle and is therefore a right triangle.
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\n" ); document.write( "The correct answer from the list of choices is (4) and the explanation is as discussed
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\n" ); document.write( "Hope this helps you to understand the problem.
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