document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148703>Question 1148703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the following.<BR>\n" );
document.write( "θ = 30°, d = 20 m\r<BR>\n" );
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document.write( "(a) Find the length of the arc that subtends the given central angle θ on a circle of diameter d.\r<BR>\n" );
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document.write( "(b) Find the area A of the sector determined by θ. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770058 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770058\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> C=pi*d, and for a 30 degree arc, it would be (30/360)*pi*d=5.24 m, length of arc.<BR>\n" );
document.write( "area is 1/12 pi*r^2 or 1/12 pi*100 cm^2=26.18 cm^3. </SPAN>\n" );
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