document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148679>Question 1148679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to make 57 ml of a 17% acid solution by mixing an 11% acid solution and a 20% acid solution. How many milliliters of each solution should the chemist use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #770028 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=770028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a quick alternative to the standard algebraic solution method shown by the other tutor  (assuming, of course, that an algebraic solution method is not required....)<br><BR>\n" );
document.write( "(1) 17% is 2/3 of the way from 11% to 20%.  (Picture the three percentages on a number line -- 11, 17, and 20.  11 to 20 is 9; 11 to 17 is 6; 6 is 2/3 of 9.)<br><BR>\n" );
document.write( "(2) That means 2/3 of the mixture must be the higher percentage ingredient.<br><BR>\n" );
document.write( "ANSWER: 2/3 of 57ml, or 38ml, of the 20% acid solution; the other 19ml of the 11% acid solution.<br><BR>\n" );
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