document.write( "Question 105752: 9. A box contains four defective and six good electronic sensors. If five sensors are drawn, with replacement,
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document.write( "find the probability of drawing
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document.write( "(a) at most one defective
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document.write( "(b) at least one defective
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document.write( "(c) fewer than three defective \n" );
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Algebra.Com's Answer #77001 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A box contains four defective and six good electronic sensors. If five sensors are drawn, with replacement, \n" ); document.write( "-------- \n" ); document.write( "P(defective)= 0.4 ; P(good)=0.6 \n" ); document.write( "------------------ \n" ); document.write( "find the probability of drawing \n" ); document.write( "(a) at most one defective \n" ); document.write( "P(at most one defective) = P(none defective)+ P(one defective) =(0.6^5)+ \n" ); document.write( "5C1[0.4^1*0.6^4] = 0.07776 + 0.2592 = 0.33696 \n" ); document.write( "---------------- \n" ); document.write( "(b) at least one defective \n" ); document.write( "P(at least one defective) = 1 - P(none defective) = 1 - (0.6^5 = 0.922 \n" ); document.write( "----------------------\r \n" ); document.write( "\n" ); document.write( "(c) fewer than three defective \n" ); document.write( "P(fewer than three defective = P(none defective)+P(one defective)+P(2 defective) \n" ); document.write( "= 0.33696 + P(2 defective) \n" ); document.write( "=0.33696 + 5C2[0.4^2*0.6^3] \n" ); document.write( "= 0.33696 + 0.3456 = 0,68256 \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |