document.write( "Question 1148622: two ships p and q left a port r at the same time on different routes.q sailed on a bearing of 150 while p sailed on the north side of q.after a distance of 8km and 10km by p and q respectively,their distance apart was 12km.find the bearing of p and r. \n" ); document.write( "

Algebra.Com's Answer #769987 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "P is 8km from R, and Q is 10km from R, and P and Q are 12km apart.

\n" ); document.write( "The bearing of Q is given: 150.

\n" ); document.write( "The bearing of P is to the north of Q. To find the bearing of Q, we need to subtract angle QRP from Q's bearing of 150.

\n" ); document.write( "Use the law of cosines on triangle QRP with side lengths 8, 10, and 12 to find the measure of angle QRP.

\n" ); document.write( " $\"12%5E2+=+10%5E2%2B8%5E2-2%288%29%2810%29cos%28x%29\"$
\n" ); document.write( " $\"160+cos%28x%29+=+100%2B64-144+=+20\"$
\n" ); document.write( " $\"x+=+arccos%281%2F8%29\"$ = 82.82 degrees to 2 decimal places.

\n" ); document.write( "ANSWER: The bearing of P is 150-82.82 = 67.18 degrees.

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