document.write( "Question 1148601: Amanda invested a total of $2,600 into three separate accounts that pay 6 %, 8 % and 10 % annual interest. Amanda has three times as much invested in the account that pays 10 % as she does in the account that pays 6 %. If the total interest for the year is $ 224, how much did Amanda invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #769959 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "Let x be the amount she investment at 6%.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Then the amount invested at 10% is 3x, and the investment at 8% is the rest (2600-x-3x) = (2600-4x) dollars.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The total interest is the sum of partial interests\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    0.06x + 0.10*(3x) + 0.08*(2600-4x) = 224   dollars.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Simplify; express x  and calculate  \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    x =  = 400 dollars.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Hence her investments are:  $400 at 6%;  $1200 at 10%  and  2600-4*400 = $1000 at 8%.    ANSWER\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "CHECK.  0.06*400 + 0.1*1200 + 0.08*1000 = 224 dollars.    ! Correct !\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );