document.write( "Question 1148550: Kelvin leaves his property to be devided between a wife,a son,and a daughter so that the wife's share to the son's share is in the ratio of 5 to 3, and the son's to daughter's in the ratio of 4 to 3.if the wife has 561,000 more than the daughter,what is the value of the property of Mr Kelvin?. \n" ); document.write( "
Algebra.Com's Answer #769917 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "wife:son = 5:3
\n" ); document.write( "son:daughter = 4:3

\n" ); document.write( "Change the ratios to equivalent ratios so that the son's share is the same number in both ratios:

\n" ); document.write( "wife:son = 20:12
\n" ); document.write( "son:daughter = 12:9

\n" ); document.write( "Now we can combine the ratios to compare all three amounts:

\n" ); document.write( "wife:son:daughter = 20:12:9

\n" ); document.write( "Now let the three amounts be 20x, 12x, and 9x.

\n" ); document.write( "We know the wife's share is 561,000 more than the daughter's share:

\n" ); document.write( "\"20x-9x+=+561000\"
\n" ); document.write( "\"11x+=+561000\"
\n" ); document.write( "\"x+=+51000\"

\n" ); document.write( "The total value of the property is

\n" ); document.write( "\"20x%2B12x%2B9x+=+41x+=+41%2851000%29+=+2091000\"

\n" ); document.write( "ANSWER: The value of the property is 2,091,000.

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