document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148572>Question 1148572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, this is a logarithmic problem. I need a step by step explanation of:<BR>\n" );
document.write( "16^log4(8). I know the answer is 64, but I need to show my work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #769904 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=769904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log (base 4) 8 = x<BR>\n" );
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document.write( "definition of logarithm gives us<BR>\n" );
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document.write( "8 = 4^x<BR>\n" );
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document.write( "x = 3/2 <BR>\n" );
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document.write( "4^(3/2) says take square root of (4^3)<BR>\n" );
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document.write( "therefore 16^(3/2) = square root(16^3) = 64<BR>\n" );
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