document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148550>Question 1148550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kelvin leaves his property to be devided between a wife,a son,and a daughter so that the wife's share to the son's share is in the ratio of 5 to 3, and the son's to daughter's in the ratio of 4 to 3.if the wife has 561,000 more than the daughter,what is the value of the property of Mr Kelvin?. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #769896 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=769896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = value of kelvin's property.<BR>\n" );
document.write( "w = his wife's share.<BR>\n" );
document.write( "s = his son's share.<BR>\n" );
document.write( "d = his daughter's share.\r<BR>\n" );
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document.write( "w/s = 5/3<BR>\n" );
document.write( "s/d = 4/3<BR>\n" );
document.write( "w = d + 561000<BR>\n" );
document.write( "p = w + s + d\r<BR>\n" );
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document.write( "in s/d = 4/3, solve for s to get s = 4d/3.\r<BR>\n" );
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document.write( "in w/s = 5/3, replace s with (4d/3) to get w/(4d/3) = 5/3<BR>\n" );
document.write( "cross multiply to get 3w = 4(4d/3)<BR>\n" );
document.write( "simplify to get 3w = 16d/3<BR>\n" );
document.write( "divide both sides of this equation by 3 to get:<BR>\n" );
document.write( "w = 16d/9\r<BR>\n" );
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document.write( "in w = d + 561000, replace w with 16d/9 to get:<BR>\n" );
document.write( "16d/9 = d + 561000<BR>\n" );
document.write( "multiply both sides of this equation by 9 to get:<BR>\n" );
document.write( "16d = 9d + 5049000<BR>\n" );
document.write( "subtract 9d from both sides of this equation to get:<BR>\n" );
document.write( "11d = 5049000<BR>\n" );
document.write( "solve for d to get:<BR>\n" );
document.write( "d = 5049000 / 11 = 459000\r<BR>\n" );
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document.write( "since w = d + 591000, solve for w to get w = 1020000\r<BR>\n" );
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document.write( "since s/d = 4/3, replace d with 459000 to get:<BR>\n" );
document.write( "s/d = s/459000 = 4/3<BR>\n" );
document.write( "cross multiply to get 3s = 4*459000<BR>\n" );
document.write( "solve for s to get s = 4*459000/3 = 612000\r<BR>\n" );
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document.write( "you have:<BR>\n" );
document.write( "w = 1020000<BR>\n" );
document.write( "s = 612000<BR>\n" );
document.write( "d = 459000\r<BR>\n" );
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document.write( "p = w + s + d = 1020000 + 612000 + 459000 = 2091000\r<BR>\n" );
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document.write( "that's your answer.<BR>\n" );
document.write( "the value of kelvin's property is 2,091,000.<BR>\n" );
document.write( "his wife's share is 1,020,000.<BR>\n" );
document.write( "his son's share is 612,000<BR>\n" );
document.write( "his daughter's share is 459,000\r<BR>\n" );
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document.write( "the ratio of his wife's share to his son's share is equal to 5/3 = 1.6666.....<BR>\n" );
document.write( "1020000/612000 = 1.6666...<BR>\n" );
document.write( "they're the same, so the ratio is correct.\r<BR>\n" );
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document.write( "the ratio of his son's share to his daughter's share is 4/3 = 1.3333.....<BR>\n" );
document.write( "612000/459000 = 1.333....<BR>\n" );
document.write( "the're the same, so the ratio is correct.\r<BR>\n" );
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document.write( "his wife's share is 561000 more than his daughter's share.<BR>\n" );
document.write( "459000 + 561000 = 1020000, so that's also correct.\r<BR>\n" );
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document.write( "add up his wife's share and his son's share and his daughter's share and your solution is that the value of kelvin's property is 2,091,000, as stated above.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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