document.write( "Question 1148521: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
\n" ); document.write( "95% confidence; n = 2388, x = 1672
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Algebra.Com's Answer #769895 by amarjeeth123(570)\"\" \"About 
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We are given that x=1672 and n=2388
\n" ); document.write( "ph=(x/n)=(1672/2388)=0.7
\n" ); document.write( "Significance level=1-confidence=1-0.95=0.05
\n" ); document.write( "Critical z-value=z(at alpha/2)=z(0.05/2)=z(at 0.025)=1.96(from z-table)
\n" ); document.write( "SE=Standard error of ph=SE=\"sqrt%28ph%2A%281-ph%29%2Fn%29\"=0.009377
\n" ); document.write( "E=Critical z-value*SE=1.96*0.009377=0.01838
\n" ); document.write( "Margin of Error=E=0.01838
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