document.write( "Question 1148521: Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level.
\n" );
document.write( "95% confidence; n = 2388, x = 1672 \n" );
document.write( "
Algebra.Com's Answer #769895 by amarjeeth123(570) ![]() You can put this solution on YOUR website! We are given that x=1672 and n=2388 \n" ); document.write( "ph=(x/n)=(1672/2388)=0.7 \n" ); document.write( "Significance level=1-confidence=1-0.95=0.05 \n" ); document.write( "Critical z-value=z(at alpha/2)=z(0.05/2)=z(at 0.025)=1.96(from z-table) \n" ); document.write( "SE=Standard error of ph=SE= \n" ); document.write( "E=Critical z-value*SE=1.96*0.009377=0.01838 \n" ); document.write( "Margin of Error=E=0.01838 \n" ); document.write( " \n" ); document.write( " |