document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148540>Question 1148540</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number 2013 has the property that its units digit is the sum of its other digits, that is 2 + 0 + 1 = 3. How many integers less than 2013 but greater than 1000 share this property?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #769883 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=769883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "1xx1: the two middle digits must sum to 0; clearly only 1 number that satisfies the condition: 1001<br><BR>\n" );
document.write( "1xx2: the two middle numbers must sum to 1; they can only be 01 or 10.  So 2 numbers: 1012 and 1102<br><BR>\n" );
document.write( "1xx3: the two middle numbers must sum to 2; they can only be 02 , 11, or 20.  So 3 numbers: 1023, 1113, and 1203<br><BR>\n" );
document.write( "...<br><BR>\n" );
document.write( "the pattern should be clear<br><BR>\n" );
document.write( "...<br><BR>\n" );
document.write( "1xx9: 9 numbers<br><BR>\n" );
document.write( "Then with leading digit 2 and less than 2013 there is only 1 number that satisfies the condition: 2002<br><BR>\n" );
document.write( "ANSWER: (1+2+3+...+9) + 1 = 45+1 = 46<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );