document.write( "Question 1148442: a man is older than his wife by 3 years. 5 years ago the ratio of their age is 4:3, find the percentage of their age \n" ); document.write( "
Algebra.Com's Answer #769803 by ankor@dixie-net.com(22740)\"\" \"About 
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a man is older than his wife by 3 years.
\n" ); document.write( "x = man's present age
\n" ); document.write( "wife is 5 yrs younger therefore:
\n" ); document.write( "(x-5) = wife's age
\n" ); document.write( ":
\n" ); document.write( " 5 years ago the ratio of their age is 4:3,
\n" ); document.write( "\"%28%28x-5%29%29%2F%28%28x-5-5%29%29\" = \"4%2F3\"
\n" ); document.write( ":
\n" ); document.write( "\"%28%28x-5%29%29%2F%28%28x-10%29%29\" = \"4%2F3\"
\n" ); document.write( "cross multiply
\n" ); document.write( "4(x-10) = 3(x-5)
\n" ); document.write( "4x - 40 = 3x - 15
\n" ); document.write( "4x - 3x = -15 + 40
\n" ); document.write( "x = 25 is the mans age
\n" ); document.write( "then obviously
\n" ); document.write( "20 = the wife's age
\n" ); document.write( ":
\n" ); document.write( " find the percentage of their age
\n" ); document.write( "\"20%2F25\" * 100 = 80% is the wife's percentage of the man's age
\n" ); document.write( "or
\n" ); document.write( "\"5%2F20\" = .25, man is 25% older than the wife
\n" ); document.write( "
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