document.write( "Question 1148442: a man is older than his wife by 3 years. 5 years ago the ratio of their age is 4:3, find the percentage of their age \n" ); document.write( "
Algebra.Com's Answer #769803 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a man is older than his wife by 3 years. \n" ); document.write( "x = man's present age \n" ); document.write( "wife is 5 yrs younger therefore: \n" ); document.write( "(x-5) = wife's age \n" ); document.write( ": \n" ); document.write( " 5 years ago the ratio of their age is 4:3, \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "4(x-10) = 3(x-5) \n" ); document.write( "4x - 40 = 3x - 15 \n" ); document.write( "4x - 3x = -15 + 40 \n" ); document.write( "x = 25 is the mans age \n" ); document.write( "then obviously \n" ); document.write( "20 = the wife's age \n" ); document.write( ": \n" ); document.write( " find the percentage of their age \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( " |