document.write( "Question 1148407: x over 2 = 3 over x????? \n" ); document.write( "
Algebra.Com's Answer #769761 by Alyssa Maserang(9)\"\" \"About 
You can put this solution on YOUR website!
x = 3
\n" ); document.write( "2 x\r
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\n" ); document.write( "\n" ); document.write( "Cross multiply:
\n" ); document.write( "x * x = 2 * 3\r
\n" ); document.write( "\n" ); document.write( "Simplifying
\n" ); document.write( "x * x = 2 * 3\r
\n" ); document.write( "\n" ); document.write( "Multiply \"x+%2A+x%0D%0Ax2+=+2+%2A+3\"\r
\n" ); document.write( "\n" ); document.write( "Multiply \"2+%2A+3%0D%0Ax2+=+6\"\r
\n" ); document.write( "\n" ); document.write( "Solving
\n" ); document.write( "\"x2+=+6\"\r
\n" ); document.write( "\n" ); document.write( "Solving for variable 'x'.
\n" ); document.write( "Move all terms containing x to the left, all other terms to the right.\r
\n" ); document.write( "\n" ); document.write( "Simplifying
\n" ); document.write( "\"x2+=+6\"
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