document.write( "Question 1148284: Two friends Ronald and Micheal live 200 miles apart. They plan to drive towards each other and meet somewhere between their houses. Ronald starts driving at 12:00 pm and drives 44 mph towards Micheal. Micheal wants to finish his favorite daytime show before he gets on the road. He doesn't start driving until 1:00 pm. He drives 60mph to try to make up for lost time. What time do the two friends meet? \n" ); document.write( "
Algebra.Com's Answer #769647 by Theo(13342) You can put this solution on YOUR website! the distance between them is 200 miles. \n" ); document.write( "ronald starts at 12:00 pm and drives 44 miles per hour. \n" ); document.write( "michael starts at 1:00 pm and drives 60 miles per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r * t = d \n" ); document.write( "r = rate \n" ); document.write( "t = time \n" ); document.write( "d = distance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for ronald, the formula becomes 44 * t = 200 - x \n" ); document.write( "for michael, the formula becomes 60 * (t - 1) = x \n" ); document.write( "simplify michael's equation to get 60 * t - 60 = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "place all variables on the left and all constants on the right to get: \n" ); document.write( "44 * t + x = 200 \n" ); document.write( "60 * t - x = 60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "those two equations need to be solved simultaneously.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add the equations together to get: \n" ); document.write( "104 * t = 260 \n" ); document.write( "the x cancels out in the addition. \n" ); document.write( "divide both sides of the equation by 104 to get: \n" ); document.write( "t = 260 / 104 = 2.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ronald traveled for 260 / 104 = 2.5 hours at 44 miles per hour for a distance of 110 miles. \n" ); document.write( "michael traveled for one hour less = 1.5 hours at 60 miles per hour for a distance of 90 miles.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ronald traveled for 2.5 hours starting at 12:00 pm = 2:30 pm \n" ); document.write( "michael traveled for 1.5 hours starting 1:00 pm = 2:30 pm.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they met each other at 2:30 pm is what i have.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |