document.write( "Question 1148284: Two friends Ronald and Micheal live 200 miles apart. They plan to drive towards each other and meet somewhere between their houses. Ronald starts driving at 12:00 pm and drives 44 mph towards Micheal. Micheal wants to finish his favorite daytime show before he gets on the road. He doesn't start driving until 1:00 pm. He drives 60mph to try to make up for lost time. What time do the two friends meet? \n" ); document.write( "
Algebra.Com's Answer #769647 by Theo(13342)\"\" \"About 
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the distance between them is 200 miles.
\n" ); document.write( "ronald starts at 12:00 pm and drives 44 miles per hour.
\n" ); document.write( "michael starts at 1:00 pm and drives 60 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "r * t = d
\n" ); document.write( "r = rate
\n" ); document.write( "t = time
\n" ); document.write( "d = distance\r
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\n" ); document.write( "\n" ); document.write( "for ronald, the formula becomes 44 * t = 200 - x
\n" ); document.write( "for michael, the formula becomes 60 * (t - 1) = x
\n" ); document.write( "simplify michael's equation to get 60 * t - 60 = x\r
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\n" ); document.write( "\n" ); document.write( "place all variables on the left and all constants on the right to get:
\n" ); document.write( "44 * t + x = 200
\n" ); document.write( "60 * t - x = 60\r
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\n" ); document.write( "\n" ); document.write( "those two equations need to be solved simultaneously.\r
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\n" ); document.write( "\n" ); document.write( "add the equations together to get:
\n" ); document.write( "104 * t = 260
\n" ); document.write( "the x cancels out in the addition.
\n" ); document.write( "divide both sides of the equation by 104 to get:
\n" ); document.write( "t = 260 / 104 = 2.5\r
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\n" ); document.write( "\n" ); document.write( "ronald traveled for 260 / 104 = 2.5 hours at 44 miles per hour for a distance of 110 miles.
\n" ); document.write( "michael traveled for one hour less = 1.5 hours at 60 miles per hour for a distance of 90 miles.\r
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\n" ); document.write( "\n" ); document.write( "ronald traveled for 2.5 hours starting at 12:00 pm = 2:30 pm
\n" ); document.write( "michael traveled for 1.5 hours starting 1:00 pm = 2:30 pm.\r
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\n" ); document.write( "\n" ); document.write( "they met each other at 2:30 pm is what i have.\r
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