document.write( "Question 1148283: A slower plane leaves LAX 2 hours before a faster plane. If the slower plane travels at 400mph and the faster plane travels at 500 mph, how long after the faster plane leaves LAX are they traveling side by side \n" ); document.write( "
Algebra.Com's Answer #769646 by MathTherapy(10557)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "A slower plane leaves LAX 2 hours before a faster plane. If the slower plane travels at 400mph and the faster plane travels at 500 mph, how long after the faster plane leaves LAX are they traveling side by side
\n" ); document.write( "
Let T be time faster plane takes to catch up to slower plane
\n" );
document.write( "Distance faster plane will travel during that time: 500T
\n" );
document.write( "Distance slower plane will travel during that time: 400(T + 2)
\n" );
document.write( "We then get the following DISTANCE equation: 500T = 400(T + 2)
\n" );
document.write( "100T = 800
\n" );
document.write( "Time faster plane takes, or \"highlight_green%28matrix%281%2C6%2C+T%2C+%22=%22%2C+800%2F100%2C+%22=%22%2C+8%2C+hours%29%29\" \n" );
document.write( "
\n" );