document.write( "Question 1148283: A slower plane leaves LAX 2 hours before a faster plane. If the slower plane travels at 400mph and the faster plane travels at 500 mph, how long after the faster plane leaves LAX are they traveling side by side \n" ); document.write( "
Algebra.Com's Answer #769640 by josmiceli(19441)\"\" \"About 
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Let \"+t+\" = time in hrs for faster plane
\n" ); document.write( "to catch up with slower plane
\n" ); document.write( "Let \"+d%5B1%5D+\" = the slower plane's head start in miles
\n" ); document.write( "Let \"+d+\" = distance the faster plane travels until it
\n" ); document.write( "catches up with the slower plane
\n" ); document.write( "-----------------------------------------------------------
\n" ); document.write( "\"+d%5B1%5D+=+400%2A2+\"
\n" ); document.write( "\"+d%5B1%5D+=+800+\"
\n" ); document.write( "Equation for slower plane:
\n" ); document.write( "(1) \"+d+-+800+=+400t+\"
\n" ); document.write( "Equation for faster plane:
\n" ); document.write( "(2) \"+d+=+500t+\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "Plug (2) into (1)
\n" ); document.write( "(1) \"+500t+-+800+=+400t+\"
\n" ); document.write( "(1) \"+100t+=+800+\"
\n" ); document.write( "(1) \"+t+=+8+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "8 hrs after the faster plane leaves LAX they are traveling side by side
\n" ); document.write( "---------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+500t+\"
\n" ); document.write( "(2) \"+d+=+500%2A8+\"
\n" ); document.write( "(2) \"+d+=+4000+\" mi
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+-+800+=+400t+\"
\n" ); document.write( "(1) \"+d+-+800+=+400%2A8+\"
\n" ); document.write( "(1) \"+d+-+800+=+3200+\"
\n" ); document.write( "(1) \"+d+=+4000+\" mi
\n" ); document.write( "OK
\n" ); document.write( "
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