document.write( "Question 1148277: Two brothers, Marco and Fernando, are training for a a marathon. Marco runs at a rate of 6 miles per hours. Fernando runs at a rate of 7.2 miles per hour. they start a training run at the same time in the same direction. In how much time wiil they be 0.3 miles apart? \n" ); document.write( "
Algebra.Com's Answer #769636 by josmiceli(19441)\"\" \"About 
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Let \"+d+\" = the distance the slower one goes
\n" ); document.write( "\"+d+%2B+.3+\" = the distance the faster one goes
\n" ); document.write( "Let \"+t+\" = the time in hrs for them to go these distances
\n" ); document.write( "------------------------
\n" ); document.write( "Marco's equation:
\n" ); document.write( "(1) \"+d+=+6t+\"
\n" ); document.write( "Fernando's equation:
\n" ); document.write( "(2) \"+d+%2B+.3+=+7.2t+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+6t+%2B+.3+=+7.2t+\"
\n" ); document.write( "(2) \"+1.2t+=+.3+\"
\n" ); document.write( "(2) \"+t+=+1%2F4+\" hrs
\n" ); document.write( "------------------------
\n" ); document.write( "In 1/4 hrs, or 15 min, they will be .3 mi apart
\n" ); document.write( "------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+6%2A%281%2F4%29+\"
\n" ); document.write( "(1) \"+d+=+1.5+\" mi
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+%2B+.3+=+7.2%2A%281%2F4%29+\"
\n" ); document.write( "(2) \"+d+=+1.8+-+.3+\"
\n" ); document.write( "(2) \"+d+=+1.5+\" mi
\n" ); document.write( "OK
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