document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148246>Question 1148246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle of radius 6 touches both coordinate axes. A line with slope -3/4 passes over and just touches the circle. If the circle is in the first quadrant, find the equation of the line. </SPAN>\n" );
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document.write( "Since the circle is in the first quadrant and touches (is tangent to) both coordinate axes, the center of the circle is (6,6).<br><BR>\n" );
document.write( "Let P be the point of tangency of the line and circle.<br><BR>\n" );
document.write( "The line has slope -3/4, so the radius to the point of tangency has a slope of 4/3.  Then, given that the radius of the circle is 6, the Pythagorean Theorem can be used to determine that P is 3.6 units to the right of and 4.8 units above the center of the circle.  So the coordinates of P are (6+3.6,6+4.8) = (9.6,10.8).<br><BR>\n" );
document.write( "You now have the slope of the line and a point on the line; there are many ways to get from there to an equation of the line.  I leave that much of the problem for you....<br><BR>\n" );
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