document.write( "Question 1148201: How do i make a quadratic equation from vertex point (4,-3) and point (6,-1)? \n" ); document.write( "
Algebra.Com's Answer #769595 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Start with the vertex form of the equation, as tutor @MathTherapy did: \n" ); document.write( " \n" ); document.write( "With the vertex given as (4,-3), the equation in this form is \n" ); document.write( " \n" ); document.write( "Then here is an alternative method for determining the value of a to complete the equation. \n" ); document.write( "(1) The point other than the vertex that is given is 2 units to the right of the vertex. \n" ); document.write( "(2) If a were 1, so that the graph behaved like y=x^2, then the y value 2 to the right of the vertex would be 2^2=4 greater than the y value at the vertex. \n" ); document.write( "(3) But the y value 2 to the right of the vertex is only 2 greater than the y value at the vertex. \n" ); document.write( "Since the y value increased only half as much as it would have increased if a were 1, a must be 1/2. \n" ); document.write( "So the equation is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |