document.write( "Question 1148202: please help with this question.\r
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\n" ); document.write( "\n" ); document.write( "If Tanisha has 1,000$ to invest at 7% per annum compounded annually,how long will it be before she has 2,000$ ?If the compounding is continuous,how long will it be? \n" ); document.write( "

Algebra.Com's Answer #769574 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "2000 = 1000*(1+0.07)^t   where \" t \" is the time, in years.\r\n" );
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document.write( "2 = \r\n" );
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document.write( "Take the logarithm of both sides\r\n" );
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document.write( "log(2) = t*log(1.07)\r\n" );
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document.write( "t =  = 10.24 years.\r\n" );
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document.write( "ANSWER.  11 years is enough time.  10 years is not enough.\r\n" );
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