document.write( "Question 1148189: 5^x+5^y=150, x-y=1, Solve Simultaneously \n" ); document.write( "
Algebra.Com's Answer #769548 by greenestamps(13215)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "By inspection....

\n" ); document.write( "We need to add two powers of 5 to get a sum of 150. Since that sum is a whole number, the powers have to be integers.

\n" ); document.write( "5^1 = 5
\n" ); document.write( "5^2 = 25
\n" ); document.write( "5^3 = 125

\n" ); document.write( "25+125 = 150; so x and y are 2 and 3.

\n" ); document.write( "Then, since we are told that x-y=1, x is 3 and y is 2.

\n" ); document.write( "If you need an algebraic solution....

\n" ); document.write( "x-y=1 --> x = y+1

\n" ); document.write( "Then

\n" ); document.write( "\"5%5Ex%2B5%5Ey=150\"
\n" ); document.write( "\"5%5E%28y%2B1%29%2B5%5Ey+=+150\"
\n" ); document.write( "\"5%2A%285%5Ey%29%2B5%5Ey+=+150\"
\n" ); document.write( "\"6%2A5%5Ey+=+150\"
\n" ); document.write( "\"5%5Ey+=+25\"
\n" ); document.write( "\"y+=+2\"
\n" ); document.write( "\"x+=+y%2B1+=+3\"
\n" ); document.write( "
\n" );