document.write( "Question 1148177: Divide 2x^3+3x^2-50x+75 by (2x+3) and hence solve for x if 2x^3+3x^2-50x+75=0 \n" ); document.write( "
Algebra.Com's Answer #769544 by josgarithmetic(39625) ![]() You can put this solution on YOUR website! Format to begin:\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " -----------------------------------\r\n" ); document.write( "2x+3 | 2x^3 + 3x^2 -50x + 75\r\n" ); document.write( " |\r\n" ); document.write( " |\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First step: \n" ); document.write( "What is 2x^3/2x? \n" ); document.write( "x^2.\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " x^2\r\n" ); document.write( " -----------------------------------\r\n" ); document.write( "2x+3 | 2x^3 + 3x^2 -50x + 75\r\n" ); document.write( " |\r\n" ); document.write( " |\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Do what would normally be done in \"regular\" long division. You continue. \n" ); document.write( " |