document.write( "Question 1148071: The denominator of a fraction is three more than twice the numerator. If both numerator and denominator are decreased by five, the simplified result is 25. Find the original fraction. (Do NOT simplify.) \n" ); document.write( "

Algebra.Com's Answer #769438 by ikleyn(52847) $\"\"$ $\"About$

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document.write( "Let x be the numerator.\r\n" );
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document.write( "Then the denominator is  2x+3, according to the condition.\r\n" );
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document.write( "Hence, the original fraction is  .\r\n" );
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document.write( "The modified fraction is   = , and you are given that  it is  25.\r\n" );
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document.write( "It gives you an equation\r\n" );
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document.write( "     = 25.\r\n" );
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document.write( "It implies\r\n" );
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document.write( "    x - 5 = 50x - 50\r\n" );
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document.write( "    50-5 = 50x-x\r\n" );
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document.write( "    45   = 49x\r\n" );
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document.write( "    x    = \r\n" );
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document.write( "ANSWER.  The original fraction is  .\r\n" );
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document.write( "         Since the problem instructs me \"DO NOT SIMPLIFY\", I should stop at this point.\r\n" );
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\n" ); document.write( "\n" ); document.write( "My personal opinion is that most of such problems violate the notions and the rules of arithmetic and contradict them.\r
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