document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1148011>Question 1148011</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much money, invested at an interest rate of r % per year compounded continuously, will amount to A dollars after t years? (Round your answer to the nearest cent.)<BR>\n" );
document.write( "A = 15,000,    r = 4.9,    t = 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #769379 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=769379\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> formula for this would be A = P * e ^ (r * t)<BR>\n" );
document.write( "A is the future value.<BR>\n" );
document.write( "P is the present value.<BR>\n" );
document.write( "r is the interest rate per year = percent interest rate per year / 100.<BR>\n" );
document.write( "t is the number of years.<BR>\n" );
document.write( "in this formula, solve for P to get:<BR>\n" );
document.write( "P = A / e ^ (r * t)<BR>\n" );
document.write( "when A = 15000 and r = 4.9% / 100  = .049 and t = 4, the formula becomes:<BR>\n" );
document.write( "P = 15000 / e ^ (.049 * 4).<BR>\n" );
document.write( "solve for P to get:<BR>\n" );
document.write( "P = 12330.18352<BR>\n" );
document.write( "to have 15,000 dollars in 4 years compounded continuously at 4.9% per year, 12,330.18352 dollars would need to be invested now.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );