document.write( "Question 1147971: Use the given data to find the minimum sample size required to estimate the population proportion Margin of error 0.008, confidence level: 98%; p and q unknown \n" ); document.write( "
Algebra.Com's Answer #769351 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! minimum sample size(n) = N * X/(X +N -1) \n" ); document.write( ": \n" ); document.write( "X = (z*)^2 * p * q/(margin of error)^2 \n" ); document.write( ": \n" ); document.write( "margin of error = 0.008 \n" ); document.write( ": \n" ); document.write( "confidence level = 98%, therefore z* = 2.33 \n" ); document.write( ": \n" ); document.write( "since p and q are not known, we make the following estimates p = 0.50, q = 0.50, population size(N) is 100,000 \n" ); document.write( ": \n" ); document.write( "X = (2.33)^2 * (0.50) * (0.50)/(0.008) = 169.6531 \n" ); document.write( ": \n" ); document.write( "n = 100000 * 169.6531/(169.6531 +100000 -1) = 169.3675 \n" ); document.write( ": \n" ); document.write( "************************** \n" ); document.write( "minimum sample size is 170 \n" ); document.write( "************************** \n" ); document.write( ": \n" ); document.write( " |