document.write( "Question 1147914: A family drives 123 miles in 2 hours, then goes another 4 miles in 15 minutes, then travels another 191 miles in 3 3/4 hours. What was their average speed to the nearest tenth of a mile per hour? \n" ); document.write( "

Algebra.Com's Answer #769297 by ikleyn(52832) $\"\"$ $\"About$

You can put this solution on YOUR website!
.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " The solution by @josgarithmetic is WRONG,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " so I came to bring the correct solution.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "Total Miles of Distance\r\n" );
document.write( "\r\n" );
document.write( "    123 + 4 + 191 = 318\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Total Hours of Time\r\n" );
document.write( "\r\n" );
document.write( "    2 +  +  = 6 hours.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Average speed is total miles divided by total time   = 53 miles per hour.    ANSWER\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );