document.write( "Question 1147958: A Standard rectangular shipping box has a length which is 3.5 inches more than its height. The width is 3 inches less than its height. What is the height of the box if its volume is 561 cubic inches? \n" ); document.write( "
Algebra.Com's Answer #769295 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "height: x
\n" ); document.write( "width: x-3
\n" ); document.write( "length: x+3.5

\n" ); document.write( "volume = length * width* height

\n" ); document.write( "\"x%28x-3%29%28x%2B3.5%29+=+561\"

\n" ); document.write( "Probably solve using a graphing calculator....

\n" ); document.write( "Or, if you are really good with mental arithmetic, solve by trial and error:

\n" ); document.write( "561 = 11*51 = 3*11*17

\n" ); document.write( "The problem says two of the dimensions differ by 3; and the factors 11 and 17 differ by 6. That might lead you to

\n" ); document.write( "3*11*17 = 12*(11/2)*(17/2)

\n" ); document.write( "And those dimensions satisfy the conditions of the problem:
\n" ); document.write( "x = 17/2 = 8.5
\n" ); document.write( "x-3 = 11/2 = 5.5
\n" ); document.write( "x+3.5 = 17/2+7/2 = 24/2 = 12

\n" ); document.write( "ANSWER: the height of the box is x = 8.5 inches.

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