document.write( "Question 1147795: Frank is eight years older than his sister. In three years he will be twice as old as she is. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #769131 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "(1) Algebra....

\n" ); document.write( "let x be his sister's age
\n" ); document.write( "then x+8 is his age

\n" ); document.write( "His sister's age 3 years from now will be x+3; his age 3 years from now will be x+11.

\n" ); document.write( "3 years from now, his age will be twice his sister's age:

\n" ); document.write( "\"x%2B11+=+2%28x%2B3%29\"

\n" ); document.write( "Solve using basic algebra (I leave that to you).

\n" ); document.write( "(2) Logical reasoning....

\n" ); document.write( "Since the difference in their ages is 8 years, Frank will be twice as old when he is 16 and his sister is 8. Since that will be 3 years from now, their current ages are 13 and 5.

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