document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105743>Question 105743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of equations\r<BR>\n" );
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document.write( "2x+y=1<BR>\n" );
document.write( "y=1-2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76911 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a \"trick\" problem to see how observant you are ... You are given the two equations:<BR>\n" );
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document.write( "2x+y=1<BR>\n" );
document.write( "y=1-2x<BR>\n" );
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document.write( "Let's rearrange the bottom equation by adding 2x to both sides. When you do that the bottom<BR>\n" );
document.write( "equation becomes 2x+y = 1. But that is identical to the top equation. Therefore, the bottom<BR>\n" );
document.write( "equation and the top equation are identical. Every solution for the top equation is a solution<BR>\n" );
document.write( "for the bottom equation also. They are not independent equations and therefore they do <BR>\n" );
document.write( "not have a single, unique solution.<BR>\n" );
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document.write( "Hope this helps you to see your way through the problem and why the answer is what it is ...<BR>\n" );
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