document.write( "Question 1147657: Hi\r
\n" ); document.write( "\n" ); document.write( "the units digit of a two digit number is one more than the tens digit. If the digits are reversed the new number is 3 less than twice the original number . What is the number.\r
\n" ); document.write( "\n" ); document.write( "I sent this question earlier but I omitted some information. \r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #769018 by MathTherapy(10557)\"\" \"About 
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\n" ); document.write( "Hi\r
\n" ); document.write( "\n" ); document.write( "the units digit of a two digit number is one more than the tens digit. If the digits are reversed the new number is 3 less than twice the original number . What is the number.\r
\n" ); document.write( "\n" ); document.write( "I sent this question earlier but I omitted some information. \r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "
Let the tens and units digits be T and U, respectively
\n" ); document.write( "Then we get: U = T + 1 ------ eq (i)
\n" ); document.write( "Also, 10U + T = 2(10T + U) - 3
\n" ); document.write( "10U + T = 20T + 2U - 3
\n" ); document.write( "3 = 20T - T + 2U - 10U
\n" ); document.write( "3 = 19T - 8U ----------- eq (ii)
\n" ); document.write( "3 = 19T - 8(T + 1) ----- Substituting T + 1 for U in eq (ii)
\n" ); document.write( "3 = 19T - 8T - 8
\n" ); document.write( "3 + 8 = 19T - 8T
\n" ); document.write( "11 = 11T
\n" ); document.write( "T, or tens digit = \"matrix%281%2C3%2C+11%2F11%2C+%22=%22%2C+1%29\"
\n" ); document.write( "U = 1 + 1 = 2 ------- Substituting 1 for T in eq (i)
\n" ); document.write( "U, or units digit = 2\r
\n" ); document.write( "\n" ); document.write( "Number: 12 \n" ); document.write( "
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