document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1147657>Question 1147657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi\r<BR>\n" );
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document.write( "the units digit of a two digit number is one more than the tens digit. If the digits are reversed the new number is 3 less than twice the original number . What is the number.\r<BR>\n" );
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document.write( "I sent this question earlier but I omitted some information. \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #769011 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=769011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let T = the tens digit.<BR>\n" );
document.write( "let U = the units digit.<BR>\n" );
document.write( "the number will be 10T + U.<BR>\n" );
document.write( "the new number with the digits reversed will be 10U + T.<BR>\n" );
document.write( "you are given that the units digits is one more than the tens digit.<BR>\n" );
document.write( "this means that U = T + 1<BR>\n" );
document.write( "you are given that the new number is 3 less than twice the original number.<BR>\n" );
document.write( "this means that 10U + T = 2 * (10T + U) - 3<BR>\n" );
document.write( "your two equations that need to be solved simultaneously are:<BR>\n" );
document.write( "U = T + 1<BR>\n" );
document.write( "10U + T = 2 * (10T + U) - 3<BR>\n" );
document.write( "simplify the second equation and leave the first equation as is to get:<BR>\n" );
document.write( "U = T + 1<BR>\n" );
document.write( "10U + T = 20T + 2U - 3<BR>\n" );
document.write( "place the variables on the left side of each equation and the constants on the right side of each equation to get:<BR>\n" );
document.write( "U - T = 1<BR>\n" );
document.write( "8U - 19T = -3<BR>\n" );
document.write( "multiply both sides of the first equation by -8 and leave the second equation as is to get:<BR>\n" );
document.write( "-8U + 8T = -8<BR>\n" );
document.write( "8U - 19T = -3<BR>\n" );
document.write( "add both equations together to get:<BR>\n" );
document.write( "-11T = -11<BR>\n" );
document.write( "solve for T to get:<BR>\n" );
document.write( "T = 1<BR>\n" );
document.write( "since U = T + 1, then U = 2<BR>\n" );
document.write( "the number is 12.<BR>\n" );
document.write( "the new number with the digits reversed is 21.<BR>\n" );
document.write( "the units digits is 1 more than the tens digits.<BR>\n" );
document.write( "this is true, since 2 is 1 more than 1.<BR>\n" );
document.write( "the reversed number is 3 less than two times the original number.<BR>\n" );
document.write( "this is true, since 21 = 2 * 12 - 3 = 24 - 3 = 21<BR>\n" );
document.write( "solution looks good.<BR>\n" );
document.write( "solution is that the original number is 12.<BR>\n" );
document.write( " </SPAN>\n" );
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