document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1147660>Question 1147660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve this exercise using the fact that the sum of the measures of the three angles of a triangle is 180\r<BR>\n" );
document.write( "\n" );
document.write( "In a​ triangle, the measures of the three angles are​ x,x+17, and x-38. What is the measure of each​ angle?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #769009 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=769009\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + x + 17 + x - 38 = 180<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "3x - 21 = 180<BR>\n" );
document.write( "add 21 to both sides to get:<BR>\n" );
document.write( "3x = 201<BR>\n" );
document.write( "solve for x to get:<BR>\n" );
document.write( "x = 67<BR>\n" );
document.write( "you get:<BR>\n" );
document.write( "x = 67<BR>\n" );
document.write( "x + 17 = 84<BR>\n" );
document.write( "x - 38 = 29<BR>\n" );
document.write( "x + x + 17 + x - 38 = 67 + 84 + 29 = 180<BR>\n" );
document.write( "each angle measures:<BR>\n" );
document.write( "67, 84, 29 degrees.<BR>\n" );
document.write( "that's your solution. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );