document.write( "Question 1147618: The odd integers are arranged into sets, each succeeding set continuing from the previous, and containing one more number as follows: {1},{3,5},{7,9,11},{13,15,17,19},... what is the sum of the numbers in the 22nd set? \n" ); document.write( "
Algebra.Com's Answer #768986 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The number of numbers in the first 21 sets is \n" ); document.write( "1+2+3+...+20+21 = (21*22)/2 = 231 \n" ); document.write( "The numbers in the 22nd set are the 22 odd numbers starting with the 232nd odd number -- i.e., the 232nd through the 253rd odd numbers. \n" ); document.write( "So the sum of the numbers in the 22nd set is \n" ); document.write( "463+465+...+505 = 22*((463+505)/2) = 11*968 = 10648 \n" ); document.write( "Another path to the answer, after finding the answer is the sum of the 232nd through the 253rd odd number.... \n" ); document.write( "The sum of the first n odd numbers is n^2. So the sum of the 232nd through 253rd odd number is the sum of the first 253 odd numbers minus the sum of the first 231 odd numbers: \n" ); document.write( "253^2-231^2 = 10648 \n" ); document.write( " \n" ); document.write( " |